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实现调用加壳的外壳中的子程序的一点见解

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发表于 2008-9-28 16:31:53 | 显示全部楼层 |阅读模式
<P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">加壳往往是实现对原</SPAN><SPAN lang=EN-US>PE</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的节数据加密、压缩,若能加壳的同时,让加壳后的程序调用壳中的某些子程序,那加壳强度大大增加。这样处理后,即使脱掉了壳,程序执行也肯定不正常,因为脱壳的同时也将这些子程序脱掉了!</SPAN><SPAN lang=EN-US> </SPAN></P>. V# _. X% m1 [6 \  x, N
<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">怎样实现呢?作为探讨性的介绍,还是搞一个最基本的来说(假设现在您已经会写</SPAN><SPAN lang=EN-US>PE-exe</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">、</SPAN><SPAN lang=EN-US>PE-dll</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">等</SPAN><SPAN lang=EN-US>PE</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">加壳程序):</SPAN><SPAN lang=EN-US> </SPAN></P>
2 N7 x# j  y4 |' D3 l4 t- R9 y! P8 I<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">我的实现是这样的:作为一个</SPAN><SPAN lang=EN-US>PE</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">文件,多多少少程序中会有</SPAN><SPAN lang=EN-US>mov eax,1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">或</SPAN><SPAN lang=EN-US>mov eax,0</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的语句,就是从这里开刀,因为</SPAN><SPAN lang=EN-US>mov eax,xxxxxxxx</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">这样的指令长度正好与</SPAN><SPAN lang=EN-US>Call xxxxxxxx</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">指令的长度一样,处理起来相对简单。在加壳程序加壳时,查找这些语句统统换成:</SPAN><SPAN lang=EN-US> </SPAN></P>; [! l& J# S! |; D1 \
<P class=MsoNormal><SPAN lang=EN-US>call shellSub </SPAN></P>/ f3 {# z& K7 Z& q, \* ~% q* u( z! h. a
<P class=MsoNormal><SPAN lang=EN-US>// </SPAN></P>
" S8 F8 J/ P8 X* Q% c: u- C1 {<P class=MsoNormal><SPAN lang=EN-US>shellSub</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">实现如下:</SPAN><SPAN lang=EN-US> </SPAN></P>
: u; B) r- d3 Z7 h" r8 M$ A<P class=MsoNormal><SPAN lang=EN-US>shellSub() </SPAN></P>! H# J; ?& m# s  @9 o# e
<P class=MsoNormal><SPAN lang=EN-US>{ </SPAN></P>
3 m( o; `- s- @7 r7 Q3 e+ }3 [- D<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp; </SPAN>mov eax,1 </SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">或</SPAN><SPAN lang=EN-US> mov eax,0 </SPAN></P>
7 M: L6 A; g9 u+ R0 Q- i( H<P class=MsoNormal><SPAN lang=EN-US>} </SPAN></P>; J( t' x2 P3 i0 J0 q& n
<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">当然,这里有个问题是怎样计算这个</SPAN><SPAN lang=EN-US>Call xxxxxxxx</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的</SPAN><SPAN lang=EN-US>xxxxxxxx</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">,其实想一想也很简单,加壳时候我们已经计算出了外壳程序的入口</SPAN><SPAN lang=EN-US>RVA</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">,只要以这个</SPAN><SPAN lang=EN-US>RVA</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">为基准,就可以得到</SPAN><SPAN lang=EN-US>:(shellSub</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的</SPAN><SPAN lang=EN-US>RVA)-(mov eax,1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的</SPAN><SPAN lang=EN-US>RVA)</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的差值,这个差值再减去</SPAN><SPAN lang=EN-US>5</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">(</SPAN><SPAN lang=EN-US>Call</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">的指令长度)就是</SPAN><SPAN lang=EN-US>xxxxxxxx</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">。</SPAN><SPAN lang=EN-US> </SPAN></P>
. k" T0 i5 r5 n' @<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">这里仅仅抛砖引玉的介绍了最基本的方法,其实通过变化,可以对原程序的很多特定语句实现改成调用外壳中不同的</SPAN><SPAN lang=EN-US>sub</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">,大大增加了外壳的保密强度。</SPAN><SPAN lang=EN-US> </SPAN></P>% X9 }, \7 R, T# D& k. [5 {
<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">这样处理后,可想而知,脱壳后的运行情况:</SPAN><SPAN lang=EN-US>Windows</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">错误,某个地址不能为读或写。。呵呵,要的就是这个效果!!!</SPAN><SPAN lang=EN-US> </SPAN></P>8 g! C( A, j* K/ ], O
<P class=MsoNormal><SPAN lang=EN-US><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;&nbsp; </SPAN></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">错误之处,恳请各位高手指正!</SPAN><SPAN lang=EN-US> </SPAN></P>
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